To find a mean proportional to two given straight lines. | ||
Let AB and BC be the two given straight lines.
It is required to find a mean proportional to AB and BC. | ||
Place them in a straight line, and describe the semicircle ADC on AC. Draw BD from the point B at right angles to the straight line AC, and join AD and DC. | I.11 | |
Since the angle ADC is an angle in a semicircle, it is right. | III.31 | |
And, since, in the right-angled triangle ADC, BD has been drawn from the right angle perpendicular to the base, therefore BD is a mean proportional between the segments of the base, AB and BC. | VI.8,Cor | |
Therefore a mean proportional BD has been found to the two given straight lines AB and BC. | ||
Q.E.F. |
This construction is used in the proofs of propositions VI.25, X.27, and X.28.
Book VI Introduction - Proposition VI.12 - Proposition VI.14.