Math 326, April 9 - Gene Propogation

If a disease is transmitted genetically, are we able to predict the percentage of the population which suffers from that disease over time?  After all, if the disease is fatal or otherwise impedes reproduction, fewer and fewer children carrying the guilty gene will be born.

Section 7.3 models this passing of genes using the Hardy-Weinberg principle.  Each gene comes with two sides, one from the mother and one from the father.  Suppose for a particular gene, each side could be either A or B.  Each person is either AA, AB or BB, with the proportions of each in the total population denoted P(AA), P(AB) and P(BB).

Suppose in addition that configuration is assigned a fertility rate e between 0 and 1.  For instance, if AA and AB individuals are healthy but BB represents a disease where 20% of sufferers die before reproducing, then we could set e(AA)=1, e(AB)=1 and e(BB)=0.8.  Each generation, we determine the number of offspring each group has based on its proportion of the population and its fertility rate.  We assume mating is random, so that A's and B's are distributed in the next generation according to the probability of each configuration.

The proportions in the population do eventually approach an equilibrium, but it takes a long time.  Check the proportions after 500 generations.  Make a 100% stacked area graph of the first 100 generations to illustrate how the population approaches its equilibria.

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